5sin^2x-7cosx+1=0

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Solution for 5sin^2x-7cosx+1=0 equation:


Simplifying
5sin2x + -7cosx + 1 = 0

Reorder the terms:
1 + -7cosx + 5in2sx = 0

Solving
1 + -7cosx + 5in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -7cosx + -1 + 5in2sx = 0 + -1

Reorder the terms:
1 + -1 + -7cosx + 5in2sx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -7cosx + 5in2sx = 0 + -1
-7cosx + 5in2sx = 0 + -1

Combine like terms: 0 + -1 = -1
-7cosx + 5in2sx = -1

Add '-5in2sx' to each side of the equation.
-7cosx + 5in2sx + -5in2sx = -1 + -5in2sx

Combine like terms: 5in2sx + -5in2sx = 0
-7cosx + 0 = -1 + -5in2sx
-7cosx = -1 + -5in2sx

Divide each side by '-7osx'.
c = 0.1428571429o-1s-1x-1 + 0.7142857143in2o-1

Simplifying
c = 0.1428571429o-1s-1x-1 + 0.7142857143in2o-1

Reorder the terms:
c = 0.7142857143in2o-1 + 0.1428571429o-1s-1x-1

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